{"id":14454,"date":"2020-06-05T17:05:19","date_gmt":"2020-06-05T17:05:19","guid":{"rendered":"https:\/\/www.devopsschool.com\/blog\/?p=14454"},"modified":"2021-11-05T10:37:39","modified_gmt":"2021-11-05T10:37:39","slug":"how-to-print-the-number-in-reverse-order-in-php-embedded-in-html-4","status":"publish","type":"post","link":"https:\/\/www.devopsschool.com\/blog\/how-to-print-the-number-in-reverse-order-in-php-embedded-in-html-4\/","title":{"rendered":"How to print the number in reverse order in PHP embedded in HTML? -4"},"content":{"rendered":"\n

How to print the number in reverse order in PHP?<\/p>\n\n\n\n

In this program, you’ll learn to reverse a number using a while loop.<\/p>\n\n\n\n

Logic:<\/p>\n\n\n\n

  1. First of all, the remainder of $num<\/var> divided by 10 is stored in the variable $rem. Now, $rem contains the last digit of $num, i.e. 3.<\/li>
  2. $rem is then added to the variable $rev after multiplying it by 10.<\/li>
  3. Multiplication by 10 adds a new place in the $rev contains. $rev contain like this 0 * 10 + 3 = 3.<\/li>
  4. $num is then divided by 10 so that now it only contains first two digits: 12.<\/li>
  5. After second iteration, $rem equals 2, $rev<\/var> equals 3 * 10 + 2 = 32 and $num<\/var> = 1.<\/li>
  6. After third iteration, $rem equals 2, $rev<\/var> equals 32 * 10 + 1 = 321 and $num<\/var> = 0.<\/li>
  7. Now, $num will be existed outside the while loop and $rev contains 321.<\/li><\/ol>\n\n\n\n

    Now , look at this coding<\/p>\n\n\n\n