Write a Shell Bash Script for check if a provided number is Armstrong or not
I’m Rajesh Kumar, a DevOps, SRE, DevSecOps, Cloud, and Platform Engineering expert passionate about sharing practical knowledge, real-world experiences, and industry best practices. I have worked at Cotocus and regularly write about technology, travel, investing, health, product reviews, and digital marketing through my various platforms.
I publish technical articles at DevOps School, travel stories at Holiday Landmark, stock market insights at Stocks Mantra, health and fitness guidance at My Medic Plus, product reviews at TrueReviewNow, and SEO and digital marketing strategies at Wizbrand.
Find Trusted Cardiac Hospitals
Compare heart hospitals by city and services — all in one place.
Explore Hospitals
#Your’s is wrong and works only for 3 digits but this one works flawlessly
#!/bin/bash
read -p “Enter Number:” num
temp=$num
arm=0
count=${#num}
if [ $num -lt 10 ]
then
echo “$num is armstrong number (1-9)”
else
while [ $num -gt 0 ]
do
rem=$((num%10))
arm=$((arm + rem**count))
num=$((num/10))
done
if [ $arm -eq $temp ]
then
echo “$arm = $temp Armstrong Number!”
else
echo “$arm != $temp Not a Armstrong Number!”
fi
fi